1. **State the problem:** We need to find the length of side $x$ in a right triangle where one leg is 6 units and the angle opposite to $x$ is $70^\circ$.
2. **Identify the sides and angle:** The side of length 6 is adjacent to the $70^\circ$ angle, and $x$ is the hypotenuse.
3. **Formula used:** In a right triangle, the cosine of an angle is the ratio of the adjacent side to the hypotenuse:
$$\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$$
4. **Apply the formula:**
$$\cos(70^\circ) = \frac{6}{x}$$
5. **Solve for $x$:**
$$x = \frac{6}{\cos(70^\circ)}$$
6. **Calculate the cosine:**
$$\cos(70^\circ) \approx 0.3420$$
7. **Substitute and compute:**
$$x = \frac{6}{0.3420} \approx 17.54$$
8. **Final answer:** The length of $x$ is approximately **17.54** units.
Triangle Length 7Ad65F
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