1. **State the problem:** We have a right triangle with legs of lengths $a$ and 6 yards, and a hypotenuse of 10 yards. We need to find the perimeter, which is the sum of all three sides. 2. **Use the Pythagorean theorem:** For a right triangle, the relationship between the legs and hypotenuse is given by: $$a^2 + 6^2 = 10^2$$ 3. **Calculate $a$:** $$a^2 + 36 = 100$$ $$a^2 = 100 - 36$$ $$a^2 = 64$$ $$a = \sqrt{64} = 8$$ 4. **Find the perimeter:** The perimeter $P$ is the sum of all sides: $$P = a + 6 + 10 = 8 + 6 + 10 = 24$$ 5. **Answer:** The perimeter of the triangle is 24 yards.