1. **State the problem:** We are given three points $F(2,9)$, $G(-7,0)$, and $H(-1,1)$ that form a triangle. We need to find the perimeter of this triangle.
2. **Formula used:** The perimeter of a triangle is the sum of the lengths of its sides. The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the distance formula:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
3. **Calculate each side length:**
- Length $FG$:
$$FG = \sqrt{(-7 - 2)^2 + (0 - 9)^2} = \sqrt{(-9)^2 + (-9)^2} = \sqrt{81 + 81} = \sqrt{162}$$
- Length $GH$:
$$GH = \sqrt{(-1 + 7)^2 + (1 - 0)^2} = \sqrt{6^2 + 1^2} = \sqrt{36 + 1} = \sqrt{37}$$
- Length $HF$:
$$HF = \sqrt{(2 + 1)^2 + (9 - 1)^2} = \sqrt{3^2 + 8^2} = \sqrt{9 + 64} = \sqrt{73}$$
4. **Simplify and approximate:**
$$FG \approx \sqrt{162} = \sqrt{81 \times 2} = 9\sqrt{2} \approx 12.7$$
$$GH \approx \sqrt{37} \approx 6.1$$
$$HF \approx \sqrt{73} \approx 8.5$$
5. **Find the perimeter:**
$$\text{Perimeter} = FG + GH + HF \approx 12.7 + 6.1 + 8.5 = 27.3$$
**Final answer:** The perimeter of the triangle is approximately $27.3$ units.
Triangle Perimeter 73Aa51
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