1. **State the problem:**
We are given a right triangle with legs 20 cm and 13 cm, and a hypotenuse of 14.7 cm (which seems inconsistent, so we will verify).
2. **Check the triangle validity using the Pythagorean theorem:**
The Pythagorean theorem states:
$$a^2 + b^2 = c^2$$
where $a$ and $b$ are legs and $c$ is the hypotenuse.
Calculate:
$$20^2 + 13^2 = 400 + 169 = 569$$
$$14.7^2 = 216.09$$
Since $569 \neq 216.09$, the given hypotenuse 14.7 cm is incorrect for a right triangle with legs 20 cm and 13 cm.
3. **Assuming the hypotenuse is the side labeled 30 cm (likely the correct hypotenuse), verify:**
$$20^2 + 13^2 = 569$$
$$30^2 = 900$$
Still not equal, so 30 cm is not the hypotenuse either.
4. **Re-examine the problem:**
The problem states the perimeter is 77.7 cm and area is 395.55 cm².
5. **Calculate perimeter:**
Sum of sides = $20 + 13 + 14.7 = 47.7$ cm, which does not match 77.7 cm.
6. **Calculate area:**
Area of right triangle = $\frac{1}{2} \times \text{leg}_1 \times \text{leg}_2$
$$= \frac{1}{2} \times 20 \times 13 = 130 \text{ cm}^2$$
This does not match 395.55 cm².
7. **Conclusion:**
The given side lengths and measurements are inconsistent for a right triangle.
8. **If the base is 30 cm (an extension), and legs are 20 cm and 13 cm, the perimeter and area given are likely for a different figure or a composite shape.
**Final answer:**
The given data is inconsistent for a right triangle with the stated sides and measurements.
Please verify the side lengths or provide additional information for accurate calculations.
Triangle Perimeter Area Efac35
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.