1. **State the problem:** We need to find the coordinates of triangle \(\triangle DEF\) after a rotation of 270° clockwise around the origin. The original vertices are \(D(-9,-7)\), \(E(-9,-1)\), and \(F(-3,-7)\).
2. **Formula for rotation:** A rotation of 270° clockwise around the origin is equivalent to a 90° counterclockwise rotation. The formula for a 90° counterclockwise rotation of a point \((x,y)\) is:
$$ (x,y) \to (-y, x) $$
3. **Apply the rotation to each vertex:**
- For \(D(-9,-7)\):
$$ (-9,-7) \to (-(-7), -9) = (7, -9) $$
- For \(E(-9,-1)\):
$$ (-9,-1) \to (-(-1), -9) = (1, -9) $$
- For \(F(-3,-7)\):
$$ (-3,-7) \to (-(-7), -3) = (7, -3) $$
4. **Final answer:** The vertices of the rotated triangle \(\triangle D'E'F'\) are:
$$ D'(7,-9), E'(1,-9), F'(7,-3) $$
This completes the rotation of the triangle 270° clockwise around the origin.
Triangle Rotation 39C86E
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