1. **State the problem:** We have a triangle with vertices A(0, 2), B(-10, 1), and C(-9, 6). We need to rotate this triangle 270° clockwise about the origin. 2. **Formula for rotation:** Rotating a point $(x,y)$ 270° clockwise about the origin is equivalent to rotating it 90° counterclockwise. The formula for 90° counterclockwise rotation is: $$ (x,y) \to (-y, x) $$ 3. **Apply the rotation to each vertex:** - For A(0, 2): $$ (0, 2) \to (-2, 0) $$ - For B(-10, 1): $$ (-10, 1) \to (-1, -10) $$ - For C(-9, 6): $$ (-9, 6) \to (-6, -9) $$ 4. **Final rotated coordinates:** - A' = (-2, 0) - B' = (-1, -10) - C' = (-6, -9) These are the new vertices of the triangle after a 270° clockwise rotation about the origin.