1. **State the problem:** We have a triangle with points A, C, B and a segment AD inside it, where AD = 64 units and DB = 28 units. On the base CB, segments CE = 20.7 units and EB = 16.1 units. We want to find a solution related to these segments, likely involving lengths or ratios. 2. **Identify what is given and what to find:** The problem shows segments on the triangle and base line. Since AD and DB are parts of AB, AB = AD + DB = 64 + 28 = 92 units. 3. **Use the segment addition and ratio properties:** Since CE and EB are parts of CB, CB = CE + EB = 20.7 + 16.1 = 36.8 units. 4. **Check for similarity or ratio relations:** If AD is a segment inside the triangle, and E lies on CB, possibly AD and E relate via similar triangles or segment division. 5. **Calculate ratio of CE to EB:** $$\frac{CE}{EB} = \frac{20.7}{16.1} \approx 1.2857$$ 6. **Calculate ratio of AD to DB:** $$\frac{AD}{DB} = \frac{64}{28} = \frac{\cancel{4} \times 16}{\cancel{4} \times 7} = \frac{16}{7} \approx 2.2857$$ 7. **Interpretation:** The ratios are different, so if the problem is to check if E divides CB in the same ratio as D divides AB, the answer is no. 8. **Final answer:** The length of AB is 92 units, the length of CB is 36.8 units, and the ratios of segments on AB and CB are different. If the problem requires a specific unknown, please clarify.