1. **Problem statement:** Calculate the area of the shape consisting of a right triangle attached to a semicircle on the left. The semicircle has radius 4 meters, and the triangle has a base of 12 meters and height of 8 meters. 2. **Formulas used:** - Area of a semicircle: $$A = \frac{1}{2} \pi r^2$$ - Area of a triangle: $$A = \frac{1}{2} bh$$ 3. **Calculate the area of the semicircle:** $$A = \frac{1}{2} \times 3.14 \times 4^2$$ $$A = \frac{1}{2} \times 3.14 \times 16$$ $$A = \frac{1}{2} \times 50.24$$ $$A = 25.12\ \text{m}^2$$ 4. **Calculate the area of the triangle:** $$A = \frac{1}{2} \times 12 \times 8$$ $$A = \frac{1}{2} \times 96$$ $$A = 48\ \text{m}^2$$ 5. **Calculate the total area:** $$A_{total} = 25.12 + 48 = 73.12\ \text{m}^2$$ 6. **Final answer:** $$\boxed{73.12\ \text{m}^2}$$