1. **State the problem:**
We have triangle $\triangle STU$ with side $s = 250$ inches opposite angle $S$, angle $\angle U = 17^\circ$, and angle $\angle S = 52^\circ$. We need to find the length of side $t$ opposite angle $T$.
2. **Find the missing angle:**
The sum of angles in a triangle is $180^\circ$.
$$\angle T = 180^\circ - \angle S - \angle U = 180^\circ - 52^\circ - 17^\circ = 111^\circ$$
3. **Use the Law of Sines:**
The Law of Sines states:
$$\frac{s}{\sin(\angle S)} = \frac{t}{\sin(\angle T)}$$
4. **Plug in known values:**
$$\frac{250}{\sin(52^\circ)} = \frac{t}{\sin(111^\circ)}$$
5. **Solve for $t$:**
Multiply both sides by $\sin(111^\circ)$:
$$t = \frac{250}{\sin(52^\circ)} \times \sin(111^\circ)$$
6. **Calculate sine values:**
$$\sin(52^\circ) \approx 0.7880$$
$$\sin(111^\circ) \approx 0.9336$$
7. **Substitute and simplify:**
$$t = \frac{250}{0.7880} \times 0.9336$$
8. **Intermediate step with cancellation:**
$$t = 250 \times \frac{0.9336}{\cancel{0.7880}} \times \cancel{\frac{1}{0.7880}}$$
9. **Calculate final value:**
$$t \approx 250 \times 1.1849 = 296.2$$
10. **Answer:**
The length of side $t$ is approximately **296.2 inches** to the nearest tenth.
Triangle Side Length 7Ca94B
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