1. **State the problem:** We have a right triangle $\triangle GHI$ with $\angle I = 90^\circ$, $\angle G = 59^\circ$, and the leg adjacent to $\angle G$ (side $h$) is 67 m. We need to find the length of side $g$, which is opposite $\angle G$. 2. **Recall the trigonometric relationship:** In a right triangle, the tangent of an angle is the ratio of the opposite side to the adjacent side: $$\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$$ Here, $\theta = 59^\circ$, opposite side is $g$, and adjacent side is $h = 67$ m. 3. **Set up the equation:** $$\tan(59^\circ) = \frac{g}{67}$$ 4. **Solve for $g$:** $$g = 67 \times \tan(59^\circ)$$ 5. **Calculate $\tan(59^\circ)$:** Using a calculator, $\tan(59^\circ) \approx 1.6643$. 6. **Find $g$:** $$g = 67 \times 1.6643 = 111.48$$ 7. **Round to the nearest metre:** $$g \approx 111\text{ m}$$ **Answer:** The length of side $g$ is approximately 111 m. Note: The options given (79 m, 131 m, 218 m) do not include 111 m, so the closest is 131 m if forced to choose from the options, but mathematically the answer is 111 m.