1. **State the problem:** We have two triangles, \(\triangle ABC\) and \(\triangle EDC\), sharing vertex \(C\). Given sides are \(AB=9\), \(AC=12\), \(BC=10\), \(ED=k\), \(DC=x\), and \(DE=27\). We need to find the values of \(x\) and \(k\).
2. **Identify the relationship:** Since the triangles share vertex \(C\) and appear to be similar (implied by the problem), corresponding sides are proportional. The similarity ratio relates sides of \(\triangle ABC\) to \(\triangle EDC\).
3. **Set up proportions:** Corresponding sides are \(AB\) to \(ED\), \(BC\) to \(DC\), and \(AC\) to \(EC\) (or \(DE\) in the second triangle). Given \(DE=27\) corresponds to \(AC=12\), so the scale factor \(r = \frac{27}{12} = \frac{9}{4}\).
4. **Find \(x\):** Since \(BC=10\) corresponds to \(DC=x\), use the scale factor:
$$x = 10 \times r = 10 \times \frac{9}{4} = \frac{90}{4} = 22.5$$
5. **Find \(k\):** Since \(AB=9\) corresponds to \(ED=k\), use the scale factor:
$$k = 9 \times r = 9 \times \frac{9}{4} = \frac{81}{4} = 20.25$$
6. **Final answers:**
$$x = 22.5$$
$$k = 20.25$$
Triangle Sides 0Fe61C
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