1. **Problem Statement:** We have a large triangle with a base of 1 meter (100 cm) and a smaller triangle inside it at the top with a base of 25 cm. The smaller triangle's two sides are labeled $x$ and $y$. We need to find the lengths of $x$ and $y$. 2. **Understanding the problem:** The smaller triangle is similar to the larger triangle because it is inside and shares the same angles. The base of the large triangle is 100 cm, and the base of the smaller triangle is 25 cm. 3. **Similarity ratio:** Since the triangles are similar, the ratio of corresponding sides is the same. The ratio of the smaller base to the larger base is: $$\frac{25}{100} = \frac{1}{4}$$ 4. **Using the ratio:** The sides $x$ and $y$ of the smaller triangle correspond to the sides of the larger triangle. If the larger triangle's sides corresponding to $x$ and $y$ are known, we multiply them by $\frac{1}{4}$ to get $x$ and $y$. 5. **Assuming the larger triangle's sides:** Since the problem does not provide the lengths of the larger triangle's sides $x_{large}$ and $y_{large}$, we assume the large triangle is isosceles with equal sides $x_{large} = y_{large} = 1$ meter = 100 cm. 6. **Calculate $x$ and $y$:** $$x = \frac{1}{4} \times 100 = 25 \text{ cm}$$ $$y = \frac{1}{4} \times 100 = 25 \text{ cm}$$ 7. **Final answer:** The lengths of the two sides of the storage area are $x = 25$ cm and $y = 25$ cm.