Subjects geometry

Triangle Similarity 2C28Ab

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1. **State the problem:** We are given two similar triangles \(\triangle STU\) and \(\triangle FEG\) with angles and side lengths labeled. We need to complete the similarity statement and find the ratio of a side length in \(\triangle STU\) to its corresponding side length in \(\triangle FEG\). 2. **Identify corresponding angles:** Since the triangles are similar, their corresponding angles are equal. Given angles: \(\angle S = 94^\circ\), \(\angle T = 56^\circ\), \(\angle U = 30^\circ\) and \(\angle F = 94^\circ\), \(\angle E = 56^\circ\), \(\angle G = 30^\circ\). 3. **Match vertices for similarity:** Corresponding angles imply corresponding vertices: \[ \triangle STU \sim \triangle FEG \] 4. **Identify corresponding sides:** Corresponding sides are opposite corresponding angles: - Side \(ST\) corresponds to side \(FE\) - Side \(TU\) corresponds to side \(EG\) - Side \(SU\) corresponds to side \(FG\) 5. **Use given side lengths:** - \(ST = 6\), \(TU = 10\), \(SU = 12\) - \(FE = 15\), \(EG = 25\), \(FG = 30\) 6. **Calculate ratio of corresponding sides:** Choose any pair, for example \(ST\) and \(FE\): $$ \text{ratio} = \frac{ST}{FE} = \frac{6}{15} $$ 7. **Simplify the fraction:** $$ \frac{6}{15} = \frac{\cancel{3} \times 2}{\cancel{3} \times 5} = \frac{2}{5} $$ **Final answers:** - Similarity statement: \(\triangle STU \sim \triangle FEG\) - Ratio of side lengths: \(\frac{2}{5}\)
STU61012FEG15253094°56°30°94°56°30°