1. **State the problem:** We are given two similar triangles \(\triangle STU\) and \(\triangle FEG\) with angles and side lengths labeled. We need to complete the similarity statement and find the ratio of a side length in \(\triangle STU\) to its corresponding side length in \(\triangle FEG\).
2. **Identify corresponding angles:** Since the triangles are similar, their corresponding angles are equal. Given angles: \(\angle S = 94^\circ\), \(\angle T = 56^\circ\), \(\angle U = 30^\circ\) and \(\angle F = 94^\circ\), \(\angle E = 56^\circ\), \(\angle G = 30^\circ\).
3. **Match vertices for similarity:** Corresponding angles imply corresponding vertices:
\[ \triangle STU \sim \triangle FEG \]
4. **Identify corresponding sides:** Corresponding sides are opposite corresponding angles:
- Side \(ST\) corresponds to side \(FE\)
- Side \(TU\) corresponds to side \(EG\)
- Side \(SU\) corresponds to side \(FG\)
5. **Use given side lengths:**
- \(ST = 6\), \(TU = 10\), \(SU = 12\)
- \(FE = 15\), \(EG = 25\), \(FG = 30\)
6. **Calculate ratio of corresponding sides:** Choose any pair, for example \(ST\) and \(FE\):
$$ \text{ratio} = \frac{ST}{FE} = \frac{6}{15} $$
7. **Simplify the fraction:**
$$ \frac{6}{15} = \frac{\cancel{3} \times 2}{\cancel{3} \times 5} = \frac{2}{5} $$
**Final answers:**
- Similarity statement: \(\triangle STU \sim \triangle FEG\)
- Ratio of side lengths: \(\frac{2}{5}\)
Triangle Similarity 2C28Ab
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.