Subjects geometry

Triangle Similarity 5Dc460

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1. **State the problem:** We are given two similar triangles \(\triangle AFP \sim \triangle HDG\) with side lengths \(AP = 15\), \(FP = 11\), \(DG = -8x - 7\), and \(GH = -6x + 4\). We need to write an equation relating the side lengths and solve for \(x\). 2. **Write the proportion from similarity:** Since the triangles are similar, corresponding sides are proportional: $$\frac{AP}{GH} = \frac{FP}{DG}$$ Substitute the given lengths: $$\frac{15}{-6x + 4} = \frac{11}{-8x - 7}$$ 3. **Cross multiply to solve for \(x\):** $$15(-8x - 7) = 11(-6x + 4)$$ 4. **Distribute:** $$-120x - 105 = -66x + 44$$ 5. **Bring all terms involving \(x\) to one side and constants to the other:** $$-120x + 66x = 44 + 105$$ $$-54x = 149$$ 6. **Divide both sides by \(-54\):** $$x = \frac{149}{\cancel{-54}} \cancel{-1} = -\frac{149}{54}$$ 7. **Calculate the decimal value:** $$x \approx -2.76$$ **Final answer:** $$\boxed{x \approx -2.76}$$
APFHDG