1. **State the problem:** We are given two similar triangles \(\triangle AFP \sim \triangle HDG\) with side lengths \(AP = 15\), \(FP = 11\), \(DG = -8x - 7\), and \(GH = -6x + 4\). We need to write an equation relating the side lengths and solve for \(x\).
2. **Write the proportion from similarity:** Since the triangles are similar, corresponding sides are proportional:
$$\frac{AP}{GH} = \frac{FP}{DG}$$
Substitute the given lengths:
$$\frac{15}{-6x + 4} = \frac{11}{-8x - 7}$$
3. **Cross multiply to solve for \(x\):**
$$15(-8x - 7) = 11(-6x + 4)$$
4. **Distribute:**
$$-120x - 105 = -66x + 44$$
5. **Bring all terms involving \(x\) to one side and constants to the other:**
$$-120x + 66x = 44 + 105$$
$$-54x = 149$$
6. **Divide both sides by \(-54\):**
$$x = \frac{149}{\cancel{-54}} \cancel{-1} = -\frac{149}{54}$$
7. **Calculate the decimal value:**
$$x \approx -2.76$$
**Final answer:**
$$\boxed{x \approx -2.76}$$
Triangle Similarity 5Dc460
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.