1. **State the problem:** We have 6 tiles each of size 1cm² and want to find what fraction of a right-angled triangle with legs 3cm and 4cm these tiles will cover. 2. **Formula for area of right-angled triangle:** $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ 3. **Calculate the area of the triangle:** $$\text{Area} = \frac{1}{2} \times 3 \times 4 = \frac{1}{2} \times 12 = 6 \text{ cm}^2$$ 4. **Calculate the total area covered by the tiles:** Each tile covers 1 cm², so 6 tiles cover: $$6 \times 1 = 6 \text{ cm}^2$$ 5. **Find the fraction of the triangle covered by the tiles:** $$\text{Fraction} = \frac{\text{Area covered by tiles}}{\text{Area of triangle}} = \frac{6}{6}$$ 6. **Simplify the fraction:** $$\frac{\cancel{6}}{\cancel{6}} = 1$$ **Final answer:** The 6 tiles cover the entire right-angled triangle, so the fraction covered is $1$ (or 100%).