1. **State the problem:** We have triangle QRS with vertices Q(-1,9), R(4,4), and S(-3,1). The transformation rule is given by $(-x, y + 2)$. We need to find the coordinates of the transformed triangle Q'R'S'. 2. **Understand the transformation rule:** The rule $(-x, y + 2)$ means: - The x-coordinate of each vertex is negated. - The y-coordinate of each vertex is increased by 2. 3. **Apply the transformation to each vertex:** - For Q(-1,9): $$Q' = (-(-1), 9 + 2) = (1, 11)$$ - For R(4,4): $$R' = (-(4), 4 + 2) = (-4, 6)$$ - For S(-3,1): $$S' = (-(-3), 1 + 2) = (3, 3)$$ 4. **Final answer:** The vertices of triangle Q'R'S' are: $$Q'(1, 11), R'(-4, 6), S'(3, 3)$$