1. The problem asks for the translation rule that maps triangle \(\triangle STU\) to \(\triangle S'T'U'\).\n2. The given points are:\n- \(U(-9,-1)\) to \(U'(4,8)\)\n- \(T(-5,-5)\) to \(T'(8,4)\)\n- \(S(-9,-9)\) to \(S'(4,0)\)\n3. A translation rule moves every point by the same amount horizontally and vertically. The rule is generally written as \((x,y) \to (x + a, y + b)\) where \(a\) is the horizontal shift and \(b\) is the vertical shift.\n4. Calculate the horizontal shift \(a\) by subtracting the original \(x\)-coordinate from the translated \(x\)-coordinate for any point, for example, for point \(U\):\n$$a = 4 - (-9) = 4 + 9 = 13$$\n5. Calculate the vertical shift \(b\) similarly, for point \(U\):\n$$b = 8 - (-1) = 8 + 1 = 9$$\n6. Therefore, the translation rule is:\n$$ (x, y) \to (x + 13, y + 9) $$\nThis means every point of \(\triangle STU\) is moved 13 units to the right and 9 units up to get \(\triangle S'T'U'\).
Triangle Translation 323Cf6
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