1. **State the problem:** Triangle JKL has vertices J(2,4), K(3,1), and L(3,3). A translation maps point J to J'(3,3). We need to find the coordinates of K' after the same translation. 2. **Understand translation:** A translation moves every point by the same amount horizontally and vertically. The rule for translation is: $$ (x, y) \to (x + a, y + b) $$ where $a$ is the horizontal shift and $b$ is the vertical shift. 3. **Find the translation vector:** Since J(2,4) moves to J'(3,3), the translation vector is: $$ (a, b) = (3 - 2, 3 - 4) = (1, -1) $$ 4. **Apply the translation to K:** Original K is at (3,1). Applying the translation vector: $$ K' = (3 + 1, 1 + (-1)) = (4, 0) $$ 5. **Answer:** The coordinates of K' are (4, 0), which corresponds to option a. --- **Note:** The second question is not solved as per instructions to solve only the first question.