1. The problem asks to draw a triangle with vertex A at the origin, vertex B on the negative x-axis, and vertex C in the third quadrant. 2. Let's define the coordinates: - Vertex A is at the origin: $A = (0,0)$. - Vertex B lies on the negative x-axis, so its coordinates are $B = (-b,0)$ where $b > 0$. - Vertex C is in the third quadrant, so both its x and y coordinates are negative: $C = (-x,-y)$ where $x > 0$ and $y > 0$. 3. The triangle can be represented by points $A(0,0)$, $B(-b,0)$, and $C(-x,-y)$. 4. Since the problem is about drawing, the function or equation is not applicable here. 5. The key is understanding the coordinate plane quadrants: - The origin is at $(0,0)$. - The negative x-axis is all points where $y=0$ and $x<0$. - The third quadrant contains points where both $x<0$ and $y<0$. 6. This setup ensures the triangle is positioned with one vertex at the origin, one along the negative x-axis, and one in the third quadrant, forming a triangle in the lower-left part of the coordinate plane.