1. **State the problem:** Find the surface area of the triangular prism using its net. 2. **Identify the faces and their areas:** The net consists of three rectangles and two congruent triangles. 3. **Calculate the area of each rectangle:** Each rectangle has dimensions $8 \text{ ft} \times 10 \text{ ft}$. $$\text{Area of each rectangle} = 8 \times 10 = 80 \text{ ft}^2$$ 4. **Calculate the area of each triangle:** Each triangle has base $8 \text{ ft}$ and height $6.9 \text{ ft}$. $$\text{Area of each triangle} = \frac{1}{2} \times 8 \times 6.9 = 27.6 \text{ ft}^2$$ 5. **Sum the areas of all faces:** $$\text{Total surface area} = 3 \times 80 + 2 \times 27.6 = 240 + 55.2 = 295.2 \text{ ft}^2$$ 6. **Final answer:** The surface area of the triangular prism is **295.2 ft²**.