1. **State the problem:** We need to find the surface area of a triangular prism given its net with dimensions. 2. **Identify the shapes in the net:** The net consists of: - One rectangle with dimensions 13 ft by 9 ft. - Two triangles each with base 9 ft and height 15 ft. - One rectangle with dimensions 12 ft by 15 ft. 3. **Recall the surface area formula for a prism:** The surface area is the sum of the areas of all faces. 4. **Calculate the area of each face:** - Rectangle 1 area: $$13 \times 9 = 117$$ sq ft - Each triangle area: $$\frac{1}{2} \times 9 \times 15 = \frac{1}{2} \times 135 = 67.5$$ sq ft - Two triangles total area: $$2 \times 67.5 = 135$$ sq ft - Rectangle 2 area: $$12 \times 15 = 180$$ sq ft 5. **Sum all areas to find total surface area:** $$117 + 135 + 180 = 432$$ sq ft 6. **Final answer:** The surface area of the triangular prism is **432 square feet**.