1. **State the problem:** Josiah wraps a gift box shaped like a triangular prism. We need to find the total surface area of the prism, which equals the amount of wrapping paper used, in square feet. 2. **Identify the shapes in the net:** The net consists of: - Two right triangles (the bases of the prism) with legs 7.81 ft and 6 ft. - Three rectangles: one 7 ft by 6 ft, one 7 ft by 5 ft, and one 6 ft by 5 ft. 3. **Formula for surface area of a triangular prism:** $$\text{Surface Area} = 2 \times \text{Area of triangular base} + \text{Perimeter of base} \times \text{length}$$ 4. **Calculate the area of one triangular base:** $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 6 \times 7.81 = 23.43$$ 5. **Calculate the perimeter of the triangular base:** The triangle has sides 6 ft, 7.81 ft, and 7.81 ft. $$\text{Perimeter} = 6 + 7.81 + 7.81 = 21.62$$ 6. **Calculate the lateral surface area:** The length of the prism is 7 ft. $$\text{Lateral area} = \text{Perimeter} \times \text{length} = 21.62 \times 7 = 151.34$$ 7. **Calculate total surface area:** $$\text{Surface Area} = 2 \times 23.43 + 151.34 = 46.86 + 151.34 = 198.2$$ 8. **Answer:** Josiah used **198.2** square feet of wrapping paper.