1. **State the problem:** Find the volume of a triangular pyramid with base edges 3 ft and 2 ft, and height 3 ft. 2. **Formula:** The volume $V$ of a pyramid is given by $$V = \frac{1}{3} \times \text{Base Area} \times \text{Height}$$ 3. **Calculate the base area:** The base is a triangle with base length 3 ft and height 2 ft, so $$\text{Base Area} = \frac{1}{2} \times 3 \times 2 = 3 \text{ ft}^2$$ 4. **Calculate the volume:** Substitute the base area and height into the volume formula: $$V = \frac{1}{3} \times 3 \times 3$$ 5. **Simplify:** $$V = \cancel{\frac{1}{3}} \times \cancel{3} \times 3 = 3 \times 3 = 9$$ 6. **Final answer:** The volume of the triangular pyramid is $$9 \text{ cubic feet}$$