1. **Convert the vector <-3, 1> into coordinate notation.** The vector is already in coordinate notation as $\langle -3, 1 \rangle$. 2. **Convert the vector <4, -7> into coordinate notation.** The vector is already in coordinate notation as $\langle 4, -7 \rangle$. 3. **Translate triangle JKL by the rule $(x, y) \to (x - 4, y + 1)$ and find the coordinate for $L'$.** Given $L(7, 2)$, apply the translation: $$L' = (7 - 4, 2 + 1) = (3, 3)$$ So, the coordinate for $L'$ is $(3, 3)$. 4. **Translate triangle PRQ by the rule $(x, y) \to (x + 5, y - 3)$ and find the coordinate for $R'$.** Given $R(-6, -2)$, apply the translation: $$R' = (-6 + 5, -2 - 3) = (-1, -5)$$ So, the coordinate for $R'$ is $(-1, -5)$.