1. The problem states that \(\angle 1\) and \(\angle 2\) are vertical angles, and we are given \(m\angle 1 = 7x + 1\) and \(m\angle 2 = 5x + 47\). We need to find \(m\angle 2\).
2. Vertical angles are always congruent, meaning their measures are equal. So, we set the expressions equal:
$$7x + 1 = 5x + 47$$
3. Solve for \(x\):
Subtract \(5x\) from both sides:
$$7x - 5x + 1 = 47$$
Simplify:
$$2x + 1 = 47$$
Subtract 1 from both sides:
$$2x = 46$$
Divide both sides by 2:
$$x = 23$$
4. Substitute \(x = 23\) back into the expression for \(m\angle 2\):
$$m\angle 2 = 5(23) + 47 = 115 + 47 = 162$$
5. Therefore, the measure of \(\angle 2\) is \(162^\circ\).
Vertical Angles 1Fc939
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