1. **State the problem:** We have two similar cylinders. The smaller one has surface area 95 mm² and volume 60 mm³. The larger one has surface area 245 mm² and we need to find its volume. 2. **Recall the properties of similar shapes:** - Surface area scales with the square of the similarity ratio $k^2$. - Volume scales with the cube of the similarity ratio $k^3$. 3. **Find the similarity ratio $k$ using surface areas:** $$\frac{\text{Surface area of larger}}{\text{Surface area of smaller}} = k^2$$ $$\frac{245}{95} = k^2$$ $$k^2 = 2.5789$$ $$k = \sqrt{2.5789} \approx 1.606$$ 4. **Use $k$ to find the volume of the larger cylinder:** $$\frac{\text{Volume of larger}}{\text{Volume of smaller}} = k^3$$ $$\text{Volume of larger} = 60 \times (1.606)^3$$ $$= 60 \times 4.143 \approx 248.6$$ 5. **Final answer:** The volume of the larger cylinder is approximately **248.6 mm³** (to 1 decimal place).