1. **Problem statement:** We are given two points A and B, with B at coordinates (4, 6). The line L is the perpendicular bisector of the segment AB, and its equation is given as $$y = -2x + 9$$. We need to find the coordinates of point A.
2. **Key concepts:**
- The perpendicular bisector of a segment passes through the midpoint of the segment.
- It is perpendicular to the segment AB.
3. **Step 1: Find the midpoint M of AB.**
Let A have coordinates $ (x, y) $. Then the midpoint M is:
$$ M = \left( \frac{x + 4}{2}, \frac{y + 6}{2} \right) $$
4. **Step 2: Since L is the perpendicular bisector, M lies on L.**
Substitute the midpoint coordinates into the line equation:
$$ \frac{y + 6}{2} = -2 \cdot \frac{x + 4}{2} + 9 $$
Multiply both sides by 2:
$$ y + 6 = -2(x + 4) + 18 $$
Simplify the right side:
$$ y + 6 = -2x - 8 + 18 $$
$$ y + 6 = -2x + 10 $$
Subtract 6 from both sides:
$$ y = -2x + 4 $$
5. **Step 3: Use the slope condition for perpendicularity.**
The slope of line L is $-2$. The segment AB is perpendicular to L, so its slope is the negative reciprocal:
$$ m_{AB} = \frac{1}{2} $$
6. **Step 4: Write the slope formula for AB.**
$$ m_{AB} = \frac{6 - y}{4 - x} = \frac{1}{2} $$
Cross-multiply:
$$ 2(6 - y) = 4 - x $$
$$ 12 - 2y = 4 - x $$
Rearranged:
$$ -2y + x = 4 - 12 $$
$$ -2y + x = -8 $$
7. **Step 5: Substitute $y$ from step 4 into this equation.**
From step 4, we have:
$$ y = -2x + 4 $$
Substitute into the equation:
$$ -2(-2x + 4) + x = -8 $$
Simplify:
$$ 4x - 8 + x = -8 $$
$$ 5x - 8 = -8 $$
Add 8 to both sides:
$$ 5x = 0 $$
$$ x = 0 $$
8. **Step 6: Find y using $x=0$.**
$$ y = -2(0) + 4 = 4 $$
**Final answer:** The coordinates of point A are $$\boxed{(0, 4)}$$.
Voronoi Point A Cb64Bb
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