1. **State the problem:** Calculate the area of the house, the driveway, and the yard given the total property area and dimensions. 2. **Given:** - Total property area = 13110 ft² - Yard dimensions: 138 ft by 95 ft (which matches total area since $138 \times 95 = 13110$) - Driveway dimensions: 45 ft by 8 ft - Residence dimensions: 52 ft by 65 ft with a cutout of 22 ft by 30 ft 3. **Calculate the area of the driveway:** $$\text{Area}_{driveway} = 45 \times 8 = 360 \text{ ft}^2$$ 4. **Calculate the area of the residence:** - Total rectangle area of residence: $$52 \times 65 = 3380 \text{ ft}^2$$ - Cutout area: $$22 \times 30 = 660 \text{ ft}^2$$ - So, $$\text{Area}_{house} = 3380 - 660 = 2720 \text{ ft}^2$$ 5. **Calculate the area of the yard:** - Yard area is total property area minus driveway and house areas: $$\text{Area}_{yard} = 13110 - 360 - 2720 = 13110 - 3080 = 10030 \text{ ft}^2$$ 6. **Summary:** - Area of the house = $2720$ ft² - Area of the driveway = $360$ ft² - Area of the yard = $10030$ ft² These calculations use basic area formulas for rectangles and subtraction for cutouts.