1. The problem is to find the Laplace transform of $\frac{f(t)}{t}$ given that the Laplace transform of $f(t)$ is $F(s)$. 2. The formula to use is: If $\mathcal{L}\{f(t)\} = F(s)$, then $$\mathcal{L}\left\{\frac{f(t)}{t}\right\} = \int_s^\infty F(u) \, du$$ This means the Laplace transform of $\frac{f(t)}{t}$ is the integral of $F(u)$ from $s$ to infinity. 3. To apply this, you first need to know $F(s)$, the Laplace transform of $f(t)$. 4. Once $F(s)$ is known, compute the improper integral: $$\int_s^\infty F(u) \, du$$ 5. This integral gives the Laplace transform of $\frac{f(t)}{t}$. In summary, the key step is to integrate $F(u)$ from $s$ to infinity to find $\mathcal{L}\{\frac{f(t)}{t}\}$.