1. The problem is to find matrix $X$ such that $$X - \begin{bmatrix}1 & 7 \\ 3 & -2 \\ 0 & 1\end{bmatrix} = \begin{bmatrix}1 & 7 \\ 3 & -2 \\ 0 & 1\end{bmatrix}$$ 2. To isolate $X$, add the matrix $\begin{bmatrix}1 & 7 \\ 3 & -2 \\ 0 & 1\end{bmatrix}$ to both sides: $$X = \begin{bmatrix}1 & 7 \\ 3 & -2 \\ 0 & 1\end{bmatrix} + \begin{bmatrix}1 & 7 \\ 3 & -2 \\ 0 & 1\end{bmatrix}$$ 3. Add corresponding elements of the matrices: $$X = \begin{bmatrix}1+1 & 7+7 \\ 3+3 & -2+(-2) \\ 0+0 & 1+1\end{bmatrix} = \begin{bmatrix}2 & 14 \\ 6 & -4 \\ 0 & 2\end{bmatrix}$$ 4. Therefore, the matrix $X$ is: $$X = \begin{bmatrix}2 & 14 \\ 6 & -4 \\ 0 & 2\end{bmatrix}$$ This matches the second matrix shown in the problem statement. Final answer: $$X = \begin{bmatrix}2 & 14 \\ 6 & -4 \\ 0 & 2\end{bmatrix}$$