Question: User: $\frac{d}{dx}$\u00a0Find the inverse of the 3\u00d73\u00a0matrix.\u1d40=\u23a1\u23a2\n2-171\n1-111\n-703-2\u23a3\u23a4
1. **State the problem:** Find the inverse of the matrix $$A=\begin{bmatrix}2 & -17 & 1 \\ 1 & -1 & 1 \\ -7 & 0 & 3 \end{bmatrix}$$.
2. **Recall the formula:** The inverse of a matrix $$A$$ exists if $$\det(A) \neq 0$$ and is given by $$A^{-1} = \frac{1}{\det(A)} \mathrm{adj}(A)$$ where $$\mathrm{adj}(A)$$ is the adjugate matrix.
3. **Calculate the determinant $$\det(A)$$:**
$$\det(A) = 2 \begin{vmatrix} -1 & 1 \\ 0 & 3 \end{vmatrix} - (-17) \begin{vmatrix} 1 & 1 \\ -7 & 3 \end{vmatrix} + 1 \begin{vmatrix} 1 & -1 \\ -7 & 0 \end{vmatrix}$$
Calculate each minor:
$$\begin{vmatrix} -1 & 1 \\ 0 & 3 \end{vmatrix} = (-1)(3) - (1)(0) = -3$$
$$\begin{vmatrix} 1 & 1 \\ -7 & 3 \end{vmatrix} = (1)(3) - (1)(-7) = 3 + 7 = 10$$
$$\begin{vmatrix} 1 & -1 \\ -7 & 0 \end{vmatrix} = (1)(0) - (-1)(-7) = 0 - 7 = -7$$
Substitute back:
$$\det(A) = 2(-3) - (-17)(10) + 1(-7) = -6 + 170 - 7 = 157$$
Since $$\det(A) = 157 \neq 0$$, the inverse exists.
4. **Find the matrix of cofactors:**
Calculate each cofactor $$C_{ij} = (-1)^{i+j} M_{ij}$$ where $$M_{ij}$$ is the minor of element $$a_{ij}$$.
- $$C_{11} = (+1) \times \begin{vmatrix} -1 & 1 \\ 0 & 3 \end{vmatrix} = -3$$
- $$C_{12} = (-1) \times \begin{vmatrix} 1 & 1 \\ -7 & 3 \end{vmatrix} = -10$$
- $$C_{13} = (+1) \times \begin{vmatrix} 1 & -1 \\ -7 & 0 \end{vmatrix} = -7$$
- $$C_{21} = (-1) \times \begin{vmatrix} -17 & 1 \\ 0 & 3 \end{vmatrix} = -(-17 \times 3 - 1 \times 0) = -(-51) = 51$$
- $$C_{22} = (+1) \times \begin{vmatrix} 2 & 1 \\ -7 & 3 \end{vmatrix} = 2 \times 3 - 1 \times (-7) = 6 + 7 = 13$$
- $$C_{23} = (-1) \times \begin{vmatrix} 2 & -17 \\ -7 & 0 \end{vmatrix} = - (2 \times 0 - (-17) \times (-7)) = - (0 - 119) = 119$$
- $$C_{31} = (+1) \times \begin{vmatrix} -17 & 1 \\ -1 & 1 \end{vmatrix} = (-17)(1) - (1)(-1) = -17 + 1 = -16$$
- $$C_{32} = (-1) \times \begin{vmatrix} 2 & 1 \\ 1 & 1 \end{vmatrix} = - (2 \times 1 - 1 \times 1) = - (2 - 1) = -1$$
- $$C_{33} = (+1) \times \begin{vmatrix} 2 & -17 \\ 1 & -1 \end{vmatrix} = 2 \times (-1) - (-17) \times 1 = -2 + 17 = 15$$
5. **Form the cofactor matrix:**
$$\mathrm{Cof}(A) = \begin{bmatrix} -3 & -10 & -7 \\ 51 & 13 & 119 \\ -16 & -1 & 15 \end{bmatrix}$$
6. **Find the adjugate matrix $$\mathrm{adj}(A)$$ by transposing the cofactor matrix:**
$$\mathrm{adj}(A) = \begin{bmatrix} -3 & 51 & -16 \\ -10 & 13 & -1 \\ -7 & 119 & 15 \end{bmatrix}$$
7. **Calculate the inverse:**
$$A^{-1} = \frac{1}{157} \begin{bmatrix} -3 & 51 & -16 \\ -10 & 13 & -1 \\ -7 & 119 & 15 \end{bmatrix}$$
**Final answer:**
$$\boxed{A^{-1} = \frac{1}{157} \begin{bmatrix} -3 & 51 & -16 \\ -10 & 13 & -1 \\ -7 & 119 & 15 \end{bmatrix}}$$