1. **Problem statement:** Given matrices \(A = \begin{pmatrix} 2 & -3 \\ \end{pmatrix}\) and \(B = \begin{pmatrix} 1 & 0 \\ -3 & \end{pmatrix}\), calculate \(AB\).
2. **Matrix multiplication formula:** For matrices \(A\) of size \(m \times n\) and \(B\) of size \(n \times p\), the product \(AB\) is an \(m \times p\) matrix where each element is computed as:
$$ (AB)_{ij} = \sum_{k=1}^n A_{ik} B_{kj} $$
3. **Check dimensions:** Here, \(A\) is 1x2 and \(B\) is 2x1 (assuming from given entries), so multiplication is possible and result is 1x1.
4. **Calculate \(AB\):**
$$ AB = \begin{pmatrix} 2 & -3 \end{pmatrix} \times \begin{pmatrix} 1 \\ -3 \end{pmatrix} = \begin{pmatrix} 2 \times 1 + (-3) \times (-3) \end{pmatrix} = \begin{pmatrix} 2 + 9 \end{pmatrix} = \begin{pmatrix} 11 \end{pmatrix} $$
5. **Final answer:** \(AB = \begin{pmatrix} 11 \end{pmatrix}\).
This completes the first problem as per instructions.
Matrix Multiplication 6B6Eba
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