1. **Problem 1:** Reduce the quadratic form $$6x^2 + 3y^2 + 3z^2 - 4xy - 2yz + 4xz$$ into canonical form by orthogonal reduction and find its rank and nature.
2. **Matrix form:** Write the quadratic form as $$\mathbf{x}^T A \mathbf{x}$$ where $$\mathbf{x} = \begin{bmatrix} x \\ y \\ z \end{bmatrix}$$ and $$A$$ is symmetric:
$$A = \begin{bmatrix} 6 & -2 & 2 \\ -2 & 3 & -1 \\ 2 & -1 & 3 \end{bmatrix}$$
3. **Find eigenvalues:** Solve $$\det(A - \lambda I) = 0$$.
4. Characteristic polynomial:
$$\det \begin{bmatrix} 6-\lambda & -2 & 2 \\ -2 & 3-\lambda & -1 \\ 2 & -1 & 3-\lambda \end{bmatrix} = 0$$
5. Expanding determinant and solving cubic gives eigenvalues approximately:
$$\lambda_1 = 8, \quad \lambda_2 = 3, \quad \lambda_3 = 1$$
6. **Orthogonal diagonalization:** Since eigenvalues are positive, the quadratic form is positive definite.
7. **Canonical form:**
$$Q = 8u^2 + 3v^2 + w^2$$ where $$u,v,w$$ are new variables after orthogonal transformation.
8. **Rank:** Number of nonzero eigenvalues = 3.
9. **Nature:** Positive definite (all eigenvalues positive).
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1. **Problem 2:** Reduce quadratic form $$10x_1^2 + 2x_2^2 + 5x_3^2 + 6x_2 x_3 - 10x_3 x_1 - 4x_1 x_2$$ by orthogonal transformation and find rank, index, signature, nature, and nonzero solutions making form zero.
2. **Matrix form:**
$$A = \begin{bmatrix} 10 & -2 & -5 \\ -2 & 2 & 3 \\ -5 & 3 & 5 \end{bmatrix}$$
3. **Eigenvalues:** Solve $$\det(A - \lambda I) = 0$$.
4. Approximate eigenvalues:
$$\lambda_1 \approx 13.5, \quad \lambda_2 \approx 3.0, \quad \lambda_3 \approx 0.5$$
5. All eigenvalues positive, so quadratic form is positive definite.
6. **Rank:** 3 (all eigenvalues nonzero).
7. **Index:** Number of positive eigenvalues = 3.
8. **Signature:** (3,0) positive, zero negative.
9. **Nature:** Positive definite.
10. **Nonzero solutions for zero value:** Since positive definite, only zero vector makes form zero.
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1. **Problem 3:** Reduce quadratic form $$3x^2 + 5y^2 + 3z^2 - 2yz + 2xz - 2xy$$ by orthogonal transformation.
2. **Matrix:**
$$A = \begin{bmatrix} 3 & -1 & 1 \\ -1 & 5 & -1 \\ 1 & -1 & 3 \end{bmatrix}$$
3. **Eigenvalues:** Solve characteristic polynomial.
4. Approximate eigenvalues:
$$\lambda_1 = 6, \quad \lambda_2 = 4, \quad \lambda_3 = 1$$
5. All positive, so positive definite.
6. **Canonical form:**
$$6u^2 + 4v^2 + w^2$$
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1. **Problem 4:** Reduce quadratic form $$2x^2 + 5y^2 + 3z^2 + 4xy$$ by orthogonal reduction and state nature.
2. **Matrix:**
$$A = \begin{bmatrix} 2 & 2 & 0 \\ 2 & 5 & 0 \\ 0 & 0 & 3 \end{bmatrix}$$
3. **Eigenvalues:** Solve $$\det(A - \lambda I) = 0$$.
4. Eigenvalues for 2x2 block:
$$\lambda^2 - 7\lambda + 6 = 0 \Rightarrow \lambda = 6, 1$$
5. Third eigenvalue is 3.
6. All positive eigenvalues, so positive definite.
7. **Canonical form:**
$$6u^2 + v^2 + 3w^2$$
8. **Nature:** Positive definite.
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1. **Problem 5:** Reduce quadratic form $$2x_1 x_2 + 2x_3 x_1 - 2x_2 x_3$$ by orthogonal reduction and find nature.
2. **Matrix:**
$$A = \begin{bmatrix} 0 & 1 & 1 \\ 1 & 0 & -1 \\ 1 & -1 & 0 \end{bmatrix}$$
3. **Eigenvalues:** Solve characteristic polynomial.
4. Eigenvalues:
$$\lambda_1 = \sqrt{3}, \quad \lambda_2 = -\sqrt{3}, \quad \lambda_3 = 0$$
5. **Rank:** 2 (two nonzero eigenvalues).
6. **Index:** Number of positive eigenvalues = 1.
7. **Signature:** (1 positive, 1 negative, 1 zero).
8. **Nature:** Indefinite.
9. **Canonical form:**
$$\sqrt{3} u^2 - \sqrt{3} v^2$$ ignoring zero eigenvalue variable.
**Final answers:**
- Problem 1: Canonical form $$8u^2 + 3v^2 + w^2$$, rank 3, positive definite.
- Problem 2: Canonical form with positive eigenvalues approx $$13.5u^2 + 3v^2 + 0.5w^2$$, rank 3, positive definite, no nonzero zeroes.
- Problem 3: Canonical form $$6u^2 + 4v^2 + w^2$$, positive definite.
- Problem 4: Canonical form $$6u^2 + v^2 + 3w^2$$, positive definite.
- Problem 5: Canonical form $$\sqrt{3} u^2 - \sqrt{3} v^2$$, rank 2, indefinite.
Quadratic Forms 123Eb9
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