1. **State the problem:** We want to analyze the logical statement $ (p \wedge q) \Rightarrow (p \vee q) $. 2. **Recall the implication rule:** An implication $A \Rightarrow B$ is false only when $A$ is true and $B$ is false; otherwise, it is true. 3. **Analyze the components:** - $p \wedge q$ means both $p$ and $q$ are true. - $p \vee q$ means at least one of $p$ or $q$ is true. 4. **Check truth values:** - If $p \wedge q$ is true, then both $p$ and $q$ are true. - If both $p$ and $q$ are true, then $p \vee q$ is also true. 5. **Conclusion:** Since whenever the antecedent $(p \wedge q)$ is true, the consequent $(p \vee q)$ is also true, the implication $ (p \wedge q) \Rightarrow (p \vee q) $ is always true. **Final answer:** The statement $ (p \wedge q) \Rightarrow (p \vee q) $ is a tautology (always true).