1. **State the problem:** We want to find the negation of the logical expression $$\neg (x \wedge \forall y (ny = 1))$$. 2. **Recall the rules:** The negation of a conjunction $$\neg (A \wedge B)$$ is equivalent to $$\neg A \vee \neg B$$ (De Morgan's Law). 3. **Apply De Morgan's Law:** $$\neg (x \wedge \forall y (ny = 1)) = \neg x \vee \neg \forall y (ny = 1)$$ 4. **Negate the universal quantifier:** The negation of $$\forall y (ny = 1)$$ is $$\exists y \neg (ny = 1)$$. 5. **Rewrite the expression:** $$\neg x \vee \exists y (ny \neq 1)$$ 6. **Interpretation:** The negation means "either $$x$$ is false, or there exists some $$y$$ such that $$ny$$ is not equal to 1."