1. **State the problem:** Carmen wants to buy 3 different items to spend as much of her 100 as possible without exceeding it. 2. **List the items and prices:** - Jeans: 25.00 - Belt: 23.50 - Shoes: 35.00 - Skirt: 30.00 - Purse: 31.00 3. **Goal:** Find 3 items whose total price is as close to 100 as possible but not more than 100. 4. **Try combinations:** - Jeans + Belt + Skirt = 25.00 + 23.50 + 30.00 = 78.50 - Jeans + Belt + Shoes = 25.00 + 23.50 + 35.00 = 83.50 - Jeans + Skirt + Purse = 25.00 + 30.00 + 31.00 = 86.00 - Belt + Skirt + Purse = 23.50 + 30.00 + 31.00 = 84.50 - Belt + Shoes + Skirt = 23.50 + 35.00 + 30.00 = 88.50 - Jeans + Shoes + Purse = 25.00 + 35.00 + 31.00 = 91.00 5. **Check totals:** The highest total under 100 is Jeans + Shoes + Purse = 91.00. 6. **Conclusion:** Carmen can buy jeans, shoes, and a purse to spend 91.00, which is the closest to 100 without going over. --- 1. **State the problem:** Derrick made 66 baskets out of 80 attempts. Find the percent made. 2. **Formula:** Percent made = $\frac{\text{number made}}{\text{total attempts}} \times 100$ 3. **Calculate:** $$\frac{66}{80} \times 100 = 0.825 \times 100 = 82.5\%$$ 4. **Answer:** Derrick made 82.5% of his shots on the first day. --- 1. **State the problem:** Derrick made 54 baskets out of 70 attempts on the second day. Compare overall percentage to first day. 2. **Calculate second day percentage:** $$\frac{54}{70} \times 100 = 0.7714 \times 100 = 77.14\%$$ 3. **Calculate overall percentage:** Total made = 66 + 54 = 120 Total attempts = 80 + 70 = 150 $$\frac{120}{150} \times 100 = 0.8 \times 100 = 80\%$$ 4. **Compare:** First day percentage (82.5%) is higher than overall (80%) because second day percentage (77.14%) was lower. 5. **Conclusion:** Derrick's overall percentage decreased compared to the first day because he made fewer shots on the second day.