Subjects mathematical literacy

Cylindrical Can 971B28

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1. **State the problem:** We have a cylindrical can with a diameter of 7.3 cm and a height of 110 mm. We need to answer several questions about perimeter, unit conversion, volume, and surface area. 2. **Explain perimeter:** The perimeter is the total distance around a 2D shape. For a circle, the perimeter is called the circumference and is calculated as $2 \pi r$. 3. **Convert height to cm:** Given height = 110 mm. Since 10 mm = 1 cm, height in cm is: $$110 \text{ mm} = \frac{110}{10} = 11 \text{ cm}$$ 4. **Calculate volume:** - Radius $r = \frac{7.3}{2} = 3.65$ cm - Height $h = 11$ cm - Volume formula: $$V = \pi r^2 h$$ - Substitute values: $$V = 3.142 \times (3.65)^2 \times 11$$ - Calculate $r^2$: $$3.65^2 = 13.3225$$ - Volume: $$V = 3.142 \times 13.3225 \times 11 = 3.142 \times 146.5475 = 460.5 \text{ cm}^3$$ 5. **Calculate surface area of label:** - The label covers the curved surface only (no top and bottom). - Curved surface area formula: $$A = 2 \pi r h$$ - Substitute values: $$A = 2 \times 3.142 \times 3.65 \times 11$$ - Calculate intermediate: $$2 \times 3.142 = 6.284$$ $$6.284 \times 3.65 = 22.93$$ $$22.93 \times 11 = 252.23$$ - Rounded to nearest cm²: $$252 \text{ cm}^2$$ **Final answers:** 1.1 Perimeter is the total distance around a shape. 1.2 Height = 11 cm 1.3 Volume = 460.5 cm³ 1.4 Label surface area = 252 cm²
7.3 cm110 mm