Subjects mathematics

Grade 10 Math Paper 19899E

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1. Problem: Find the domain of the relation \( R = \{(0, 2), (2, 3), (3, 3), (3, 4)\} \). 2. The domain of a relation is the set of all first elements (inputs) of the ordered pairs. 3. Extract the first elements from each pair: $$\{0, 2, 3, 3\}$$ 4. Remove duplicates to get the domain: $$\{0, 2, 3\}$$ 5. Therefore, the domain of \(R\) is \(\{0, 2, 3\}\). --- 1. Problem: What is a histogram? 2. A histogram is a graphical representation of data using adjacent rectangles where the height of each rectangle represents the frequency of data in that interval. 3. Therefore, a histogram is a set of adjacent rectangles. --- 1. Problem: What is the most frequent occurring observation in a data set called? 2. The most frequent value in a data set is called the mode. --- 1. Problem: What are the observations that divide a data set into four equal parts called? 2. These observations are called quartiles. --- 1. Problem: Define an onto function. 2. An onto function (surjective) is a function where every element in the codomain has at least one pre-image in the domain. --- 1. Problem: If \(A = \mathbb{N}\) (natural numbers) and \(B = \mathbb{W}\) (whole numbers), find \(B - A\). 2. Since \(\mathbb{N} = \{1, 2, 3, ...\}\) and \(\mathbb{W} = \{0, 1, 2, 3, ...\}\), 3. \(B - A = \{0\}\). --- 1. Problem: Find the arithmetic mean by direct method for the data: 200, 225, 350, 375, 270, 320, 290. 2. Arithmetic mean formula: $$\text{Mean} = \frac{\sum x_i}{n}$$ 3. Calculate sum: $$200 + 225 + 350 + 375 + 270 + 320 + 290 = 2030$$ 4. Number of data points \(n = 7\). 5. Calculate mean: $$\frac{2030}{7} = 290$$ --- 1. Problem: Define class mark. 2. Class mark is the midpoint of a class interval, calculated as: $$\text{Class mark} = \frac{\text{Lower limit} + \text{Upper limit}}{2}$$ --- 1. Problem: Name two measures of central tendency. 2. Two common measures are mean and median. --- 1. Problem: If \(L = \{a, b, c\}\), \(M = \{d, e, f, g\}\), find two binary relations in \(L \times M\). 2. \(L \times M\) is the set of all ordered pairs \((l, m)\) where \(l \in L\) and \(m \in M\). 3. Two example binary relations: $$\{(a, d), (b, e)\}$$ $$\{(c, f), (a, g)\}$$ --- 1. Problem: If \(X = \{1, 4, 7, 9\}\), \(Y = \{2, 4, 5, 9\}\), find \(Y \cap X\). 2. Intersection \(Y \cap X\) is the set of elements common to both: $$\{4, 9\}$$ --- 1. Problem: Find \(a\) and \(b\) if \((3 - 2a, b - 1) = (a - 7, 2b + 5)\). 2. Equate components: $$3 - 2a = a - 7$$ $$b - 1 = 2b + 5$$ 3. Solve first equation: $$3 - 2a = a - 7 \Rightarrow 3 + 7 = a + 2a \Rightarrow 10 = 3a \Rightarrow a = \frac{10}{3}$$ 4. Solve second equation: $$b - 1 = 2b + 5 \Rightarrow b - 2b = 5 + 1 \Rightarrow -b = 6 \Rightarrow b = -6$$ --- 1. Problem: Define mode. 2. Mode is the value that appears most frequently in a data set. --- 1. Problem: If \(A = \{2, 3, 5, 7\}\), \(B = \{3, 5, 8\}\), find \(A \cup B\). 2. Union \(A \cup B\) is all elements in either set: $$\{2, 3, 5, 7, 8\}$$ --- 1. Problem: State De Morgan’s laws. 2. De Morgan’s laws: $$ (A \cup B)' = A' \cap B' $$ $$ (A \cap B)' = A' \cup B' $$ --- 1. Problem: For data \(X = \{12, 5, 8, 4\}\), find the harmonic mean. 2. Harmonic mean formula: $$H = \frac{n}{\sum \frac{1}{x_i}}$$ 3. Calculate sum of reciprocals: $$\frac{1}{12} + \frac{1}{5} + \frac{1}{8} + \frac{1}{4} = 0.0833 + 0.2 + 0.125 + 0.25 = 0.6583$$ 4. Number of data points \(n = 4\). 5. Calculate harmonic mean: $$H = \frac{4}{0.6583} \approx 6.08$$ --- 1. Problem: Verify \(A - B = A \cap B'\) for \(U = \{1,2,3,4,...,10\}\), \(A = \{1,3,5,7,8\}\), \(B = \{1,4,7,10\}\). 2. \(A - B = \{3,5,8\}\) (elements in A not in B). 3. \(B' = U - B = \{2,3,5,6,8,9\}\). 4. \(A \cap B' = \{3,5,8\}\). 5. Both sets are equal, so verified. --- 1. Problem: Calculate variance for data: 10, 8, 9, 7, 5, 12, 8, 6, 8, 2. 2. Variance formula: $$\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n}$$ 3. Calculate mean: $$\bar{x} = \frac{10 + 8 + 9 + 7 + 5 + 12 + 8 + 6 + 8 + 2}{10} = \frac{75}{10} = 7.5$$ 4. Calculate squared deviations and sum: $$(10-7.5)^2 = 6.25$$ $$(8-7.5)^2 = 0.25$$ $$(9-7.5)^2 = 2.25$$ $$(7-7.5)^2 = 0.25$$ $$(5-7.5)^2 = 6.25$$ $$(12-7.5)^2 = 20.25$$ $$(8-7.5)^2 = 0.25$$ $$(6-7.5)^2 = 2.25$$ $$(8-7.5)^2 = 0.25$$ $$(2-7.5)^2 = 30.25$$ Sum = 68.5 5. Calculate variance: $$\sigma^2 = \frac{68.5}{10} = 6.85$$ --- 1. Problem: Find standard deviation of salaries: 11500, 12400, 15000, 14500, 14800. 2. Mean: $$\bar{x} = \frac{11500 + 12400 + 15000 + 14500 + 14800}{5} = \frac{68200}{5} = 13640$$ 3. Squared deviations: $$(11500 - 13640)^2 = 299, 600$$ $$(12400 - 13640)^2 = 1, 537, 600$$ $$(15000 - 13640)^2 = 1, 849, 600$$ $$(14500 - 13640)^2 = 7, 344, 100$$ $$(14800 - 13640)^2 = 1, 345, 600$$ Sum = 12,376,500 4. Variance: $$\sigma^2 = \frac{12,376,500}{5} = 2,475,300$$ 5. Standard deviation: $$\sigma = \sqrt{2,475,300} \approx 1573.1$$ --- 1. Problem: Prove \((A - B)' = A' \cup B\) for \(U = \{1,2,3,4,...,10\}\), \(A = \{1,3,5,7,9\}\), \(B = \{1,4,7,10\}\). 2. \(A - B = \{3,5,9\}\). 3. \((A - B)' = U - (A - B) = \{1,2,4,6,7,8,10\}\). 4. \(A' = U - A = \{2,4,6,8,10\}\). 5. \(A' \cup B = \{1,4,7,10\} \cup \{2,4,6,8,10\} = \{1,2,4,6,7,8,10\}\). 6. Both sides equal, so proved.