1. **Problem Statement:** Solve the first question (Q1) which contains multiple parts a) to e). 2. **Part a)** Draw a triangle $\triangle ABC$ with sides $AB=5.5$ cm, $BC=4.2$ cm, and $AC=3.5$ cm. (This is a construction task, no calculation needed here.) 3. **Part b)** Given two complementary angles $y - 20$ and $y + 30$, find each angle. - Complementary angles sum to 90°, so: $$ (y - 20) + (y + 30) = 90 $$ - Simplify: $$ 2y + 10 = 90 $$ - Subtract 10 from both sides: $$ 2y + \cancel{10} - \cancel{10} = 90 - 10 $$ $$ 2y = 80 $$ - Divide both sides by 2: $$ \frac{\cancel{2}y}{\cancel{2}} = \frac{80}{2} $$ $$ y = 40 $$ - Find each angle: $$ y - 20 = 40 - 20 = 20^\circ $$ $$ y + 30 = 40 + 30 = 70^\circ $$ 4. **Part c)** Write $\frac{22}{7}$ in decimal form. - Divide 22 by 7: $$ \frac{22}{7} \approx 3.142857 $$ 5. **Part d)** Find the square root of 4096. - Since $64^2 = 4096$, $$ \sqrt{4096} = 64 $$ 6. **Part e)** Multiply $(4x + 5y) \times (9x + 7y)$. - Use distributive property: $$ (4x)(9x) + (4x)(7y) + (5y)(9x) + (5y)(7y) $$ $$ = 36x^2 + 28xy + 45xy + 35y^2 $$ - Combine like terms: $$ 36x^2 + (28xy + 45xy) + 35y^2 = 36x^2 + 73xy + 35y^2 $$ **Final answers:** - b) Angles are $20^\circ$ and $70^\circ$ - c) Decimal form is approximately 3.142857 - d) Square root is 64 - e) Product is $36x^2 + 73xy + 35y^2$