Subjects measurement

Map Distance B973A3

Step-by-step solutions with LaTeX - clean, fast, and student-friendly.

Use the AI math solver

1. **State the problem:** We have a campground map with a scale where 4 inches on the map equals 2 miles in reality. We want to find the real-world distance corresponding to 2 1/2 inches and 3 inches on the map. 2. **Formula and rules:** The scale factor relates map distance to real distance: $$\text{Real distance} = \text{Map distance} \times \frac{\text{Real miles}}{\text{Map inches}}$$ Given: 4 inches = 2 miles, so the scale factor is $\frac{2}{4} = \frac{1}{2}$ miles per inch. 3. **Calculate real distance for 2 1/2 inches:** Convert mixed number to improper fraction: $$2 \frac{1}{2} = \frac{5}{2}$$ Multiply by scale factor: $$\frac{5}{2} \times \frac{1}{2} = \frac{5}{4} = 1.25$$ miles 4. **Calculate real distance for 3 inches:** $$3 \times \frac{1}{2} = \frac{3}{2} = 1.5$$ miles 5. **Summary:** - 2 1/2 inches on the map corresponds to 1.25 miles in reality. - 3 inches on the map corresponds to 1.5 miles in reality. This method can be used to convert any map measurement to real-world distance using the given scale.