1. **State the problem:** We need to find the bearing of town C from the hiker and then determine how many degrees clockwise the hiker must turn from facing town C to face town D. 2. **Understanding bearings:** Bearings are measured clockwise from the north direction (0° or 360°) around the compass. 3. **Given information:** - The north line is at 90° on the protractor. - Town C is at approximately 50° from the vertical north line (which is at 90°). - Town D is at approximately 130° from the vertical north line. 4. **Calculate the bearing of town C from the hiker:** Since the north line is at 90° on the protractor, and town C is 50° from the north line, the bearing is: $$\text{Bearing of C} = 90^\circ - 50^\circ = 40^\circ$$ This means town C is at a bearing of 40° from the hiker. 5. **Calculate the bearing of town D from the hiker:** Similarly, town D is 130° from the north line, so: $$\text{Bearing of D} = 90^\circ - 130^\circ = -40^\circ$$ Since bearings are positive clockwise from north, we add 360° to get a positive bearing: $$-40^\circ + 360^\circ = 320^\circ$$ So town D is at a bearing of 320° from the hiker. 6. **Calculate the clockwise turn from town C to town D:** The hiker is facing town C at 40°. To face town D at 320°, the clockwise turn is: $$\text{Turn} = 320^\circ - 40^\circ = 280^\circ$$ 7. **Final answers:** - Bearing of town C from the hiker is **40°**. - The hiker must turn **280° clockwise** to face town D from town C.