1. **Problem statement:** Convert the number $124_5$ (base 5) to base 2 and base 6.
2. **Step 1: Convert from base 5 to base 10 (decimal).**
The number $124_5$ means:
$$1 \times 5^2 + 2 \times 5^1 + 4 \times 5^0$$
Calculate each term:
$$1 \times 25 = 25$$
$$2 \times 5 = 10$$
$$4 \times 1 = 4$$
Sum these:
$$25 + 10 + 4 = 39$$
So, $124_5 = 39_{10}$.
3. **Step 2a: Convert decimal 39 to base 2.**
Divide 39 by 2 repeatedly and record remainders:
- $39 \div 2 = 19$ remainder $1$
- $19 \div 2 = 9$ remainder $1$
- $9 \div 2 = 4$ remainder $1$
- $4 \div 2 = 2$ remainder $0$
- $2 \div 2 = 1$ remainder $0$
- $1 \div 2 = 0$ remainder $1$
Write remainders from last to first:
$$100111_2$$
4. **Step 2b: Convert decimal 39 to base 6.**
Divide 39 by 6 repeatedly and record remainders:
- $39 \div 6 = 6$ remainder $3$
- $6 \div 6 = 1$ remainder $0$
- $1 \div 6 = 0$ remainder $1$
Write remainders from last to first:
$$103_6$$
**Final answers:**
- (a) $124_5 = 100111_2$
- (b) $124_5 = 103_6$
Base Conversion 1B46Da
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