1. The problem is to convert the number 2426 from base 8 (octal) to base 10 (decimal). 2. The formula to convert a number from base $b$ to base 10 is: $$\text{Decimal} = \sum_{i=0}^{n-1} d_i \times b^i$$ where $d_i$ are the digits of the number starting from the right (least significant digit) and $n$ is the number of digits. 3. For the number 2426 in base 8, the digits from right to left are 6, 2, 4, 2. 4. Calculate each digit multiplied by 8 raised to the power of its position: $$2 \times 8^3 + 4 \times 8^2 + 2 \times 8^1 + 6 \times 8^0$$ 5. Calculate powers of 8: $$8^3 = 512, \quad 8^2 = 64, \quad 8^1 = 8, \quad 8^0 = 1$$ 6. Substitute and multiply: $$2 \times 512 = 1024$$ $$4 \times 64 = 256$$ $$2 \times 8 = 16$$ $$6 \times 1 = 6$$ 7. Add all the results: $$1024 + 256 + 16 + 6 = 1302$$ 8. Therefore, the base 10 equivalent of 2426 base 8 is 1302.