1. The problem is to convert the decimal number 236 to base 30p. 2. First, we need to understand the base 30p system. Assuming "p" represents a digit, but since no value is given, we treat "30p" as a base with digits 3, 0, and p, which is unclear. Likely, the user means base 30 (thirty). 3. To convert 236 from decimal to base 30, we divide 236 by 30 repeatedly and record the remainders. 4. Divide 236 by 30: $$236 \div 30 = 7 \text{ remainder } 26$$ 5. Divide 7 by 30: $$7 \div 30 = 0 \text{ remainder } 7$$ 6. The digits in base 30 are read from last remainder to first: 7 and 26. 7. Since base 30 digits go from 0 to 29, digit 26 corresponds to the letter 'Q' (if we use 0-9 for digits 0-9 and A-T for 10-29). 8. Therefore, 236 in base 30 is written as $$7Q$$. 9. Final answer: $$236_{10} = 7Q_{30}$$.