1. **State the problem:** Multiply the octal numbers 527 (base 8) and 673 (base 8).
2. **Convert octal to decimal:**
- $527_8 = 5 \times 8^2 + 2 \times 8^1 + 7 \times 8^0 = 5 \times 64 + 2 \times 8 + 7 = 320 + 16 + 7 = 343_{10}$
- $673_8 = 6 \times 8^2 + 7 \times 8^1 + 3 \times 8^0 = 6 \times 64 + 7 \times 8 + 3 = 384 + 56 + 3 = 443_{10}$
3. **Multiply the decimal equivalents:**
$$343 \times 443 = 151,849$$
4. **Convert the product back to octal:**
Divide 151,849 by 8 repeatedly and record remainders:
- $151,849 \div 8 = 18,981$ remainder $1$
- $18,981 \div 8 = 2,372$ remainder $5$
- $2,372 \div 8 = 296$ remainder $4$
- $296 \div 8 = 37$ remainder $0$
- $37 \div 8 = 4$ remainder $5$
- $4 \div 8 = 0$ remainder $4$
Reading remainders from last to first: $450451_8$
5. **Final answer:**
$$527_8 \times 673_8 = 450451_8$$
Octal Multiplication 148067
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.