1. **Problem statement:** We are given a number 85AB1 which is a multiple of 99. We need to find the digits $A$ and $B$.
2. **Key fact:** A number is divisible by 99 if and only if it is divisible by both 9 and 11.
3. **Divisibility by 9 rule:** The sum of the digits must be divisible by 9.
4. **Divisibility by 11 rule:** The difference between the sum of digits in odd positions and the sum of digits in even positions must be divisible by 11.
5. Write the digits: $8, 5, A, B, 1$.
6. Sum of digits for divisibility by 9:
$$8 + 5 + A + B + 1 = 14 + A + B$$
This sum must be divisible by 9.
7. For divisibility by 11, label positions from right to left:
- Position 1 (rightmost): 1 (odd)
- Position 2: B (even)
- Position 3: A (odd)
- Position 4: 5 (even)
- Position 5: 8 (odd)
Sum odd positions: $8 + A + 1 = 9 + A$
Sum even positions: $5 + B$
Difference:
$$ (9 + A) - (5 + B) = 4 + A - B $$
This difference must be divisible by 11.
8. Let’s analyze divisibility by 9:
Possible sums divisible by 9 near $14 + A + B$ are 18, 27, 36, ...
Since $A$ and $B$ are digits (0 to 9), max sum is $14 + 9 + 9 = 32$, so possible sums are 18 or 27.
9. Case 1: $14 + A + B = 18 \\ A + B = 4$
10. Case 2: $14 + A + B = 27 \\ A + B = 13$
11. For divisibility by 11:
$$4 + A - B = 0, \pm 11, \pm 22, ...$$
Since $A$ and $B$ are digits, difference is small, so consider:
- $4 + A - B = 0 \\ \Rightarrow B = A + 4$
- $4 + A - B = 11 \\ \Rightarrow B = A - 7$ (not possible since $B$ must be ≥ 0)
- $4 + A - B = -11 \\ \Rightarrow B = A + 15$ (not possible)
12. From $4 + A - B = 0$, we have $B = A + 4$.
13. Substitute into sums:
- Case 1: $A + B = 4 \\ A + (A + 4) = 4 \\ 2A + 4 = 4 \\ 2A = 0 \\ A = 0, B = 4$
- Case 2: $A + B = 13 \\ A + (A + 4) = 13 \\ 2A + 4 = 13 \\ 2A = 9 \\ A = 4.5$ (not an integer digit, discard)
14. Therefore, the only solution is $A=0$ and $B=4$.
15. Check divisibility:
Number: 85041
Sum digits: $8+5+0+4+1=18$ divisible by 9.
Difference for 11: $(8+0+1)-(5+4) = 9 - 9 = 0$ divisible by 11.
16. Hence, $A=0$ and $B=4$ satisfy the conditions.
**Final answer:** $A=0$, $B=4$
Digits A B 8B21Cc
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