1. **State the problem:** Find the exponent of 3 in the prime factorization of 2025.
2. **Recall the prime factorization process:** To find the exponent of a prime in a number, repeatedly divide the number by that prime until it is no longer divisible.
3. **Start dividing 2025 by 3:**
$$2025 \div 3 = 675$$
4. **Divide 675 by 3:**
$$675 \div 3 = 225$$
5. **Divide 225 by 3:**
$$225 \div 3 = 75$$
6. **Divide 75 by 3:**
$$75 \div 3 = 25$$
7. **Check if 25 is divisible by 3:** It is not, so stop here.
8. **Count the number of times 3 divides 2025:** It divides 4 times.
9. **Therefore, the exponent of 3 in the prime factorization of 2025 is:**
$$\boxed{4}$$
Exponent Of 3 C044Bf
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