1. **State the problem:** Find the remainder when $7^{222}$ is divided by 100.
2. **Formula and theorem:** We use Euler's theorem which states that if $a$ and $n$ are coprime, then
$$a^{\phi(n)} \equiv 1 \pmod{n}$$
where $\phi(n)$ is Euler's totient function.
3. **Calculate $\phi(100)$:** Since $100 = 2^2 \times 5^2$,
$$\phi(100) = 100 \times \left(1 - \frac{1}{2}\right) \times \left(1 - \frac{1}{5}\right) = 100 \times \frac{1}{2} \times \frac{4}{5} = 40$$
4. **Apply Euler's theorem:** Since $7$ and $100$ are coprime,
$$7^{40} \equiv 1 \pmod{100}$$
5. **Reduce the exponent modulo 40:**
$$222 \equiv \cancel{40 \times 5}^{200} + 22 \equiv 22 \pmod{40}$$
6. **Calculate $7^{222} \equiv 7^{22} \pmod{100}$:**
We compute powers of 7 modulo 100 stepwise:
$$7^1 = 7$$
$$7^2 = 49$$
$$7^4 = (7^2)^2 = 49^2 = 2401 \equiv 1 \pmod{100}$$
7. Since $7^4 \equiv 1 \pmod{100}$, we write
$$7^{22} = 7^{4 \times 5 + 2} = (7^4)^5 \times 7^2 \equiv 1^5 \times 49 = 49 \pmod{100}$$
**Final answer:**
$$\boxed{49}$$
Remainder 7 Power 7Aa9Bb
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