1. **Problem Statement:**
Find the value of $y$ at $x=1.75$ using Gauss's forward interpolation formula given the data points:
| $x$ | 1.72 | 1.73 | 1.74 | 1.75 | 1.76 | 1.77 |
|-----|------|------|------|------|------|------|
| $y$ | ? | ? | ? | ? | ? | ? |
(Note: Since the user did not provide $y$ values, we assume the problem is to explain the method.)
2. **Formula:**
Gauss's forward interpolation formula is:
$$
P(x) = y_0 + p\Delta y_0 + \frac{p(p-1)}{2!}\Delta^2 y_0 + \frac{p(p-1)(p-2)}{3!}\Delta^3 y_0 + \cdots
$$
where $p = \frac{x - x_0}{h}$, $h$ is the equal spacing between $x$ values, $y_0$ is the first value, and $\Delta$ denotes forward differences.
3. **Steps:**
- Calculate $h = 1.73 - 1.72 = 0.01$.
- Calculate $p = \frac{1.75 - 1.72}{0.01} = 3$.
- Construct the forward difference table for $y$ values.
- Apply the formula using the differences and $p$.
4. **Explanation:**
Gauss's forward formula uses the value at the starting point and adds corrections based on the forward differences weighted by $p$ terms.
5. **Final answer:**
Cannot compute exact $y$ without given $y$ values.
Please provide $y$ values for complete solution.
Gauss Forward 075Ecc
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