1. **State the problem:** We have an auditorium with dimensions 40.0 m by 20.0 m by 12.0 m. We want to find: (a) The volume of the room in cubic feet. (b) The weight of the air in the room in pounds. 2. **Calculate the volume in cubic meters:** The volume $V$ is given by the product of length, width, and height: $$V = 40.0 \times 20.0 \times 12.0 = 9600\ \text{m}^3$$ 3. **Convert volume to cubic feet:** We use the conversion factor: $$1\ \text{m}^3 = 35.3147\ \text{ft}^3$$ So, $$V_{ft^3} = 9600 \times 35.3147 = 338,982.72\ \text{ft}^3$$ 4. **Calculate the mass of air in the room:** Given the density of air $\rho = 1.20\ \text{kg/m}^3$, mass $m$ is: $$m = \rho \times V = 1.20 \times 9600 = 11,520\ \text{kg}$$ 5. **Convert mass to weight in pounds:** Using the conversion: $$1\ \text{kg} = 2.20462\ \text{lb}$$ So, $$W = 11,520 \times 2.20462 = 25,396.7\ \text{lb}$$ **Final answers:** (a) Volume = $338,983\ \text{ft}^3$ (rounded to nearest whole number) (b) Weight of air = $25,397\ \text{lb}$ (rounded to nearest whole number)